(3x+9/2x)/(x^2+3x^2/3x^2)

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Solution for (3x+9/2x)/(x^2+3x^2/3x^2) equation:


D( x )

((3*x^2)/3)*x^2+x^2 = 0

((3*x^2)/3)*x^2+x^2 = 0

((3*x^2)/3)*x^2+x^2 = 0

x^4+x^2 = 0

t_1 = x^2

1*t_1^2+1*t_1^1 = 0

t_1^2+t_1 = 0

DELTA = 1^2-(0*1*4)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)-1)/(1*2) or t_1 = (-1^(1/2)-1)/(1*2)

t_1 = 0 or t_1 = -1

t_1 = -1

x^2+1 = 0

1*x^2 = -1 // : 1

x^2 = -1

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x+(9/2)*x)/(((3*x^2)/3)*x^2+x^2) = 0

(15/2*x)/(x^4+x^2) = 0

x^4+x^2 = 0

x^2*(x^2+1) = 0

1*x^2 = -1 // : 1

x^2 = -1

x^2 = 0

(15/2*x)/(x^2) = 0

15/2*x = 0 // : 15/2

x = 0

x in { 0}

x belongs to the empty set

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